20p^2=3.8p+1.2=0

Solution for 20p^2=3.8p+1.2=0 equation:

20p^2=3.8p+1.2=0

We move all terms to the left:

20p^2-(3.8p+1.2)=0

We get rid of parentheses

20p^2-3.8p-1.2=0

a = 20; b = -3.8; c = -1.2;
Δ = b2-4ac
Δ = -3.82-4·20·(-1.2)
Δ = 110.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.8)-\sqrt{110.44}}{2*20}=\frac{3.8-\sqrt{110.44}}{40}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.8)+\sqrt{110.44}}{2*20}=\frac{3.8+\sqrt{110.44}}{40}
$